x^2-245x-4950=0

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Solution for x^2-245x-4950=0 equation:



x^2-245x-4950=0
a = 1; b = -245; c = -4950;
Δ = b2-4ac
Δ = -2452-4·1·(-4950)
Δ = 79825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{79825}=\sqrt{25*3193}=\sqrt{25}*\sqrt{3193}=5\sqrt{3193}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-245)-5\sqrt{3193}}{2*1}=\frac{245-5\sqrt{3193}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-245)+5\sqrt{3193}}{2*1}=\frac{245+5\sqrt{3193}}{2} $

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